The Inverse of a Logarithmic Function — Cheat sheet
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The move
x is stuck inside a logarithm, so the exponential frees it.
y=logax⟺x=ay
Method
- Write y=f(x).
- Make the logarithm stand alone: clear coefficients and constants first.
- Raise the base to both sides. It releases the whole argument.
- Undo what is left, then swap the letters.
| Function | Inverse |
|---|
| f(x)=log3x | f−1(x)=3x |
| f(x)=log2x+1 | f−1(x)=2x−1 |
| f(x)=log5(x−2) | f−1(x)=5x+2 |
| f(x)=2log3x | f−1(x)=3x/2 |
| f(x)=log4(3x) | f−1(x)=34x |
Stand alone first
23log2x=x. Divide by the 3 before raising the base:
3log2x=y⇒log2x=3y⇒x=2y/3
The whole argument comes out
5log5(x−2)=x−2. The bracket arrives intact; the −2 comes off afterwards.
Domain and range change places
| domain | range |
|---|
| f(x)=logax | x>0 | every real number |
| f−1(x)=ax | every real number | y>0 |
Which way round
| x sits... | ...so use |
|---|
| in an exponent | the logarithm |
| inside a logarithm | the exponential |