Relative Positions of Two Lines

LESSON 13 OF 16See the unit map ↗

Use slopes and intercepts to compare two lines.

Builds on Intersection of Two Lines · Finding Slope

The bigger question: How can a picture become an equation?

On this page

Idea

Two lines in a plane can only do three things. They cross at one point, they never meet, or they are the same line.

You can tell which by counting the points they share: one, none, or all of them. There is no fourth case, so one test settles it.

Rule

For a1x+b1y+c1=0a_1x + b_1y + c_1 = 0 and a2x+b2y+c2=0a_2x + b_2y + c_2 = 0, compare the ratios of coefficients:

a1a2≠b1b2⇒they intersect at one point\frac{a_1}{a_2} \ne \frac{b_1}{b_2} \Rightarrow \text{they intersect at one point} a1a2=b1b2≠c1c2⇒parallel, never meeting\frac{a_1}{a_2} = \frac{b_1}{b_2} \ne \frac{c_1}{c_2} \Rightarrow \text{parallel, never meeting} a1a2=b1b2=c1c2⇒the same line twice\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \Rightarrow \text{the same line twice}

How it is used

The ratio test and the slope test give the same answer. Use whichever suits the form you are given.

ConditionSlope viewShared points
a1a2≠b1b2\dfrac{a_1}{a_2} \ne \dfrac{b_1}{b_2}different slopesexactly one
a1a2=b1b2≠c1c2\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} \ne \dfrac{c_1}{c_2}equal slopes, different interceptsnone
a1a2=b1b2=c1c2\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} = \dfrac{c_1}{c_2}equal slopes and equal interceptsevery point

Always take the ratios in the same order: first coefficients, then second coefficients, then constants. Keep the same line on top every time.

The most common mistake is comparing a1a2\dfrac{a_1}{a_2} with b2b1\dfrac{b_2}{b_1}, with the lines swapped.

This also explains what happens when you solve the two equations.

Different slopes give one solution. Equal slopes with different constants give something false, such as 0=70 = 7, which means no shared points. If all three ratios are equal you get 0=00 = 0, which means every point is shared.

Worked example

Decide how the lines 2x−3y+1=02x - 3y + 1 = 0 and 4x−6y+5=04x - 6y + 5 = 0 are positioned. Compare the first coefficients: 24=12\dfrac{2}{4} = \dfrac{1}{2}. Compare the second: −3−6=12\dfrac{-3}{-6} = \dfrac{1}{2}, which matches, so the slopes are equal. Now the constants: 15\dfrac{1}{5}, which does not match 12\dfrac{1}{2}. Equal in the first two ratios but not the third means parallel and distinct:

24=−3−6≠15\frac{2}{4} = \frac{-3}{-6} \ne \frac{1}{5}

Explore

Drag C and D until the verdict says Parallel. Now move one of them by a single step. The verdict changes to Intersecting and a meeting point appears. Getting Coincident is harder: both C and D must sit exactly on the blue line.

Two lines, one plane

Try this. Use A(0,0), B(1,1), C(0,1), D(1,2) for parallel lines. Change D to (1,0) for perpendicular lines.

Two lines, one plane-6-6-4-4-2-2224466xyBCDintersectionA
Blue slope: -0.4 · Green slope: 1 · Intersecting at (0.857, 1.857).
PAUSE & THINKA quick check, not a grade

Try it yourself.

Choose an answer and explain your reasoning to yourself. Use a hint if you get stuck.

How are y=2x+1y=2x+1 and y=2x−3y=2x-3 positioned?

Hint 1 · Find a starting point

Compare both the slopes and the intercepts.

Hint 2 · Take the next step

The slopes agree, but the y-intercepts do not.

Show the reasoning

Answer: Parallel and distinct

They are distinct parallel lines. Equal slopes give the same direction; different intercepts prevent the lines from being the same set of points.

Before moving on: what would make one of the other answers wrong? Saying why is part of understanding.

MAKE IT YOURS

Pause before the next idea.

Can you explain how the visualization connects to this lesson’s goal? If a step still feels uncertain, put this lesson on your review list and try the check again another day.

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