Graphing Lines

LESSON 12 OF 16See the unit map ↗

Graph a line using an intercept and a slope.

Builds on Equations from Intercepts · Testing a Point Against a Line

The bigger question: How can a picture become an equation?

On this page

Idea

Two points are enough to draw a line, so you never need to plot many values.

Find two points you are sure about, mark them, and draw a straight line through them. The only skill is choosing the two points that need the least arithmetic.

Rule

To sketch ax+by+c=0ax + by + c = 0, take the two intercepts:

y=0⇒the x-intercepty = 0 \Rightarrow \text{the } x\text{-intercept} x=0⇒the y-interceptx = 0 \Rightarrow \text{the } y\text{-intercept}

Plot both, join them, and extend past both ends - a line does not stop at the points you happened to plot.

How it is used

Choose the method that matches the form you are given.

FormFastest route
ax+by+c=0ax + by + c = 0both intercepts
y=mx+ny = mx + nstart at (0,n)(0, n), then step the slope: run right, rise up
Through the originthe origin is one point; find any second
x=cx = c or y=cy = cdraw the vertical or horizontal line directly

The stepping method is worth explaining.

Start at any point on the line. A slope of 34\dfrac{3}{4} means go 44 to the right and 33 up. You land exactly on another point of the line. If the slope is negative, you go down instead of up.

Using whole numbers keeps you on grid corners, so you never have to guess a position.

Two checks catch most mistakes.

Plot a third point. If it does not sit on the same straight line, one of your three points is wrong.

Check the direction before anything else. A positive slope must rise to the right, and a negative slope must fall.

Worked example

Sketch the line 3x+4y−12=03x + 4y - 12 = 0 using its intercepts. Set y=0y = 0 to find where it crosses the xx-axis: 3x=123x = 12, so x=4x = 4, giving (4,0)(4, 0). Set x=0x = 0 to find where it crosses the yy-axis: 4y=124y = 12, so y=3y = 3, giving (0,3)(0, 3). Plot (4,0)(4, 0) and (0,3)(0, 3), join them, and extend both ways. As a check the slope should be negative, and indeed the line falls from (0,3)(0, 3) down to (4,0)(4, 0):

m=−34m = -\frac{3}{4}

Explore

Put A and B on the two intercepts of a line you are drawing, and compare it with your own sketch. Then try the stepping method: leave A on the yy-intercept and move B by exactly the run and the rise. It stays on the same line.

A line through two points

Try this. Move the two points and compare the equation. Equal x values produce a vertical line; equal points cannot define one.

A line through two points-6-6-4-4-2-2224466xyBA
y = -0.4x + 2.2 · Slope = -0.4
PAUSE & THINKA quick check, not a grade

Try it yourself.

Choose an answer and explain your reasoning to yourself. Use a hint if you get stuck.

After plotting (0,1)(0,1) for y=2x+1y=2x+1, which second point is on the line?

Hint 1 · Find a starting point

Use slope 2 as rise 2 for run 1.

Hint 2 · Take the next step

Start at (0, 1), move one right, then two up.

Show the reasoning

Answer: (1,3)(1,3)

You reach (1, 3). Two distinct points determine the line; connecting arbitrary axis increments can give the wrong slope.

Before moving on: what would make one of the other answers wrong? Saying why is part of understanding.

MAKE IT YOURS

Pause before the next idea.

Can you explain how the visualization connects to this lesson’s goal? If a step still feels uncertain, put this lesson on your review list and try the check again another day.

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