Arctan and Arccot — Cheat sheet

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Definitions

y=arctan⁡x  ⟺  tan⁡y=xy = \arctan x \iff \tan y = x, with D=(−∞,∞)D = (-\infty, \infty) and R=(−π2,π2)R = \left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right).

y=arccot x  ⟺  cot⁡y=xy = \text{arccot}\,x \iff \cot y = x, with D=(−∞,∞)D = (-\infty, \infty) and R=(0,π)R = (0, \pi).

Both accept every real number. Both ranges are open: the ends are approached, never reached.

Negative inputs

FunctionRuleLike
arctan⁡(−x)=−arctan⁡x\arctan(-x) = -\arctan xodd - flips signarcsin
arccot(−x)=π−arccot x\text{arccot}(-x) = \pi - \text{arccot}\,xreflects - never negativearccos

−45∘-45^\circ and 315∘315^\circ are the same point, but arctan reports −45∘-45^\circ - the reading inside its range.

Exact values

xx−3-\sqrt{3}−1-1−13-\dfrac{1}{\sqrt{3}}0013\dfrac{1}{\sqrt{3}}113\sqrt{3}
arctan⁡x\arctan x−60∘-60^\circ−45∘-45^\circ−30∘-30^\circ0∘0^\circ30∘30^\circ45∘45^\circ60∘60^\circ
arccot x\text{arccot}\,x150∘150^\circ135∘135^\circ120∘120^\circ90∘90^\circ60∘60^\circ45∘45^\circ30∘30^\circ

arccot 0=90∘\text{arccot}\,0 = 90^\circ, while arctan⁡0=0\arctan 0 = 0. That difference catches people out.

Asymptotes

Arctan flattens towards ±π2\pm\dfrac{\pi}{2}; arccot towards 00 and π\pi. Every real input, and the output never leaves a fixed interval - the standard example when limits at infinity are taught.

Identities

IdentityCondition
tan⁡(arctan⁡x)=x\tan(\arctan x) = xany real xx
cot⁡(arccot x)=x\cot(\text{arccot}\,x) = xany real xx
arctan⁡x+arccot x=π2\arctan x + \text{arccot}\,x = \dfrac{\pi}{2}any real xx - the conversion between them

All four inverses, side by side

FunctionRangeQuadrantsNegative input
arcsin⁡\arcsin[−π2,π2]\left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]first, fourthnegative angle
arctan⁡\arctan(−π2,π2)\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)first, fourthnegative angle
arccos⁡\arccos[0,π][0, \pi]first, secondobtuse angle
arccot\text{arccot}(0,π)(0, \pi)first, secondobtuse angle

When there is no special angle

Name it α\alpha. For arctan, tan⁡α\tan\alpha is opposite over adjacent; for arccot, cot⁡α\cot\alpha is adjacent over opposite. Draw the triangle, let Pythagoras give the hypotenuse, read off whatever is asked. The angle itself is never needed.