The Unit Circle

Read sine and cosine from a point on the unit circle.

Builds on Values at 30, 45 and 60 Degrees

The bigger question: How does an angle become a number?

On this page

Idea

The triangle got you this far, but it has an edge it cannot cross. At 0, 90, 180, 270 and 360 degrees the angle lands on an axis. There is no triangle there, so the right-triangle definitions cannot help.

The circle can. Draw a circle of radius 11 and let the angle xx sweep from the positive horizontal axis. The angle lands on the point (cos⁡x,sin⁡x)(\cos x, \sin x) - that point is the definition from now on, and it works at every angle, axis or not. Calculus reads sine and cosine off this circle, and so will the rest of this module.

Rule

Cosine is the first coordinate, sine the second. Read them straight off the point.

(cos⁡0∘,sin⁡0∘)=(1,0)(\cos 0^\circ, \sin 0^\circ) = (1, 0)

(cos⁡90∘,sin⁡90∘)=(0,1)(\cos 90^\circ, \sin 90^\circ) = (0, 1)

(cos⁡180∘,sin⁡180∘)=(−1,0)(\cos 180^\circ, \sin 180^\circ) = (-1, 0)

(cos⁡270∘,sin⁡270∘)=(0,−1)(\cos 270^\circ, \sin 270^\circ) = (0, -1)

(cos⁡360∘,sin⁡360∘)=(1,0)(\cos 360^\circ, \sin 360^\circ) = (1, 0)

One full turn ends where it began, so 0∘0^\circ and 360∘360^\circ share a point. That is periodicity: sin⁡(x+360∘)=sin⁡x\sin(x + 360^\circ) = \sin x for every angle.

How it is used

AngleRadiansPointcos⁡\cossin⁡\sintan⁡\tancot⁡\cot
0∘0^\circ00(1,0)(1, 0)110000undefined
90∘90^\circπ2\dfrac{\pi}{2}(0,1)(0, 1)0011undefined00
180∘180^\circπ\pi(−1,0)(-1, 0)−1-10000undefined
270∘270^\circ3π2\dfrac{3\pi}{2}(0,−1)(0, -1)00−1-1undefined00
360∘360^\circ2π2\pi(1,0)(1, 0)110000undefined

Why tangent and cotangent break in opposite places

Neither is a coordinate. Both are built from the two coordinates, and each fails when its own bottom is 00.

tan⁡x=sin⁡xcos⁡x\tan x = \frac{\sin x}{\cos x} cot⁡x=cos⁡xsin⁡x\cot x = \frac{\cos x}{\sin x}
Attan⁡\tancot⁡\cot
0∘0^\circ, 180∘180^\circ, 360∘360^\circ00undefined
90∘90^\circ, 270∘270^\circundefined00

Where one is zero the other is undefined. On a graph these are the vertical asymptotes of each curve.

The special angles land here too

The values from the last lesson have not gone anywhere. At 30∘30^\circ, 45∘45^\circ and 60∘60^\circ the point on this circle is (cos⁡x,sin⁡x)(\cos x, \sin x) with the exact values you already know - the hypotenuse is 11, so each leg is its own ratio. Check them in the Explore below.

Worked example

Evaluate tan⁡π+cos⁡2π+sin⁡3π2\tan\pi + \cos 2\pi + \sin\dfrac{3\pi}{2}.

Remember

π=180∘\pi = 180^\circ, half a turn. 2π=360∘2\pi = 360^\circ, a full one degrees →\rightarrow radians: ×π180\times \dfrac{\pi}{180} radians →\rightarrow degrees: ×180π\times \dfrac{180}{\pi} 3π2→3π2⋅180π=270∘\dfrac{3\pi}{2} \rightarrow \dfrac{3\pi}{2} \cdot \dfrac{180}{\pi} = 270^\circ

  1. Convert, since the circle is labelled in degrees.
tan⁡180∘+cos⁡360∘+sin⁡270∘\tan 180^\circ + \cos 360^\circ + \sin 270^\circ
  1. Tangent is not a coordinate. Build it from the point at 180∘180^\circ, which is (−1,0)(-1, 0).
tan⁡180∘⏟sin⁡180∘cos⁡180∘=0−1=0\underbrace{\tan 180^\circ}_{\frac{\sin 180^\circ}{\cos 180^\circ} = \frac{0}{-1}} = 0
  1. The other two are coordinates. At 360∘360^\circ the point is (1,0)(1, 0), at 270∘270^\circ it is (0,−1)(0, -1).
0+cos⁡360∘⏟1+sin⁡270∘⏟−10 + \underbrace{\cos 360^\circ}_{1} + \underbrace{\sin 270^\circ}_{-1}
  1. Add the three.
0+1−1=00 + 1 - 1 = 0

A zero on the bottom breaks a quotient. A zero on the top does not, which is why tan⁡180∘\tan 180^\circ is 00 rather than undefined.

The unit circle

Try this. Try 0°, 90°, 180° and 270°. The horizontal projection is cosine; the vertical projection is sine. Track their signs between axes.

The unit circleP11270°
θ = 270° = 1.5π rad · cos θ = 0 · sin θ = -1 · sin² θ + cos² θ = 1
The unit circle

Try this. Try 0°, 90°, 180° and 270°. The horizontal projection is cosine; the vertical projection is sine. Track their signs between axes.

The unit circleP11180°
θ = 180° = 1π rad · cos θ = -1 · sin θ = 0
PAUSE & THINKA quick check, not a grade

Try it yourself.

Choose an answer and explain your reasoning to yourself. Use a hint if you get stuck.

At angle π/2\pi/2, what is (cos⁡θ,sin⁡θ)(\cos\theta,\sin\theta)?

Hint 1 · Find a starting point

Start at the positive x axis and rotate counterclockwise.

Hint 2 · Take the next step

A quarter turn reaches the top of the unit circle.

Show the reasoning

Answer: (0,1)(0,1)

The top point is (0, 1). Cosine is the horizontal coordinate and sine the vertical coordinate.

Before moving on: what would make one of the other answers wrong? Saying why is part of understanding.

Explore

Drag from 6060 degrees up to 9090. The cos leg shrinks to nothing, and tan - sine divided by that shrinking number - grows huge, then reads undefined at 9090 exactly. Cross to 105105 and tan returns, large and negative.

Then drag to 360360: the readings are 00's again. One full turn changes nothing. On the way, stop at 3030, 4545 and 6060 and check the readouts against the table you learned last lesson.

The unit circle

Try this. Try 0°, 90°, 180° and 270°. The horizontal projection is cosine; the vertical projection is sine. Track their signs between axes.

The unit circleP1160°
θ = 60° = 0.333π rad · cos θ = 0.5 · sin θ = 0.866
MAKE IT YOURS

Pause before the next idea.

Can you explain how the visualization connects to this lesson’s goal? If a step still feels uncertain, put this lesson on your review list and try the check again another day.

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