y=arcsinx⟺siny=x with y∈[−2π,2π].
D=[−1,1], R=[−2π,2π].
Values worth knowing
x
arcsinx
−1
−2π
−21
−6π
0
0
21
6π
22
4π
1
2π
Inverting
Trapped inside
Apply
sin(…)
arcsin to both sides
arcsin(…)
sin to both sides
Non-standard ratios
Let α be the inverse expression, draw the right triangle with that opposite side and hypotenuse, and use Pythagoras for the third side. Read any function of α off it.
The complementary sum
x2+y2=1⇒arcsinx+arcsiny=2π - the two legs of a unit-hypotenuse triangle, so the angles are complementary.