For an expression u(x), solve u(x)=0 to locate the breakpoints before splitting into intervals.
Example
For ∣2x−6∣, the breakpoint is x=3. If x<3, then 2x−6<0 and the value is 6−2x. If x≥3, the value is 2x−6. Both branches meet at zero when x=3, producing a corner rather than a discontinuity.
Avoid this mistake
∣a+b∣ is not generally ∣a∣+∣b∣. For a=1,b=−1, the two sides are 0 and 2.