Functions That Are Not Onto

LESSON 20 OF 27See the unit map ↗

Identify codomain values that a function does not reach.

The bigger question: What does a function tell us—and what can it hide?

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Idea

Some texts call a function “into” when its range is a proper subset of its codomain. Because terminology varies, “not onto” is the clearer statement. Such a function leaves at least one declared target unreachable.

Visual guide

VISUAL GUIDEAn unused codomain value

Range is smaller than the codomain

The codomain here is {0, 1, 2}, but the outputs actually reached are {0, 1}. The missing arrow into 2 makes the function not onto this codomain. Onto depends on the declared codomain.ab012
The codomain here is {0, 1, 2}, but the outputs actually reached are {0, 1}. The missing arrow into 2 makes the function not onto this codomain. Onto depends on the declared codomain.

Method

To disprove onto behavior, exhibit a single element of the codomain with no preimage. You must know the codomain before making this judgment.

Worked example

For f:R→Rf:\mathbb R\to\mathbb R with f(x)=x2f(x)=x^2, the target −1-1 cannot be reached by a real input. Thus ff is not onto. If instead the declared codomain is [0,∞)[0,\infty), every target yy has preimage y\sqrt y, so the same formula and domain become onto that codomain.

PAUSE & THINKA quick check, not a grade

Try it yourself.

Choose an answer and explain your reasoning to yourself. Use a hint if you get stuck.

Why is f: ℝ → ℝ, f(x)=eˣ, not onto?

Hint 1 · Find a starting point

Onto depends on the declared codomain.

Hint 2 · Take the next step

The codomain is ℝ but the actual outputs are positive.

Show the reasoning

Answer: It never produces a nonpositive output.

For example, no real x satisfies eˣ=0, so some codomain values are missed.

Before moving on: what would make one of the other answers wrong? Saying why is part of understanding.

Common mistake

A function can be one-to-one without being onto, or onto without being one-to-one. These are independent properties.

Check your understanding

Is ex:R→Re^x:\mathbb R\to\mathbb R onto?

Show answer

No. Zero and all negative targets are unreachable; its range is (0,∞)(0,\infty).

MAKE IT YOURS

Pause before the next idea.

Can you explain how the visualization connects to this lesson’s goal? If a step still feels uncertain, put this lesson on your review list and try the check again another day.

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