Determinants, Orientation and Invertibility

Interpret a determinant as signed volume scaling and compute it using row operations.

Builds on Change of Basis and Similarity

The bigger question: Is the vector changing, or only the coordinates used to describe it?

On this page

Measure how a square map scales volume

For A=(abcd)A=\begin{pmatrix}a&b\\c&d\end{pmatrix}, det⁡A=ad−bc\det A=ad-bc. Its absolute value is the area scaling factor, while its sign records whether orientation is preserved or reversed. A zero determinant means the unit square collapses into a lower-dimensional set.

In nn dimensions the determinant similarly gives signed nn-dimensional volume scaling. Only square matrices have determinants. A square matrix is invertible exactly when its determinant is nonzero, but computing a determinant is often not the best numerical test for near-singularity.

Visual guide

VISUAL GUIDEThe determinant measures signed area scaling
Columns (2, 0) and (1, 1) enclose a parallelogram of area 2, so the determinant is 2. Swapping the columns preserves geometric area but reverses orientation and changes the determinant’s sign.-0.5-0.50.50.1251.50.752.51.383.52xyarea = 2
Columns (2, 0) and (1, 1) enclose a parallelogram of area 2, so the determinant is 2. Swapping the columns preserves geometric area but reverses orientation and changes the determinant’s sign.

Worked example: area and orientation

For A=(2103)A=\begin{pmatrix}2&1\\0&3\end{pmatrix}, determinant 66 means a unit square becomes a parallelogram of area 66, with orientation preserved. A reflection diag⁡(−1,1)\operatorname{diag}(-1,1) has determinant −1-1: it preserves area but reverses orientation.

Composition multiplies scaling factors, yielding det⁡(AB)=det⁡Adet⁡B\det(AB)=\det A\det B. Consequently det⁡(A−1)=1/det⁡A\det(A^{-1})=1/\det A when an inverse exists. Determinants are not generally additive.

PAUSE & THINKA quick check, not a grade

Try it yourself.

Choose an answer and explain your reasoning to yourself. Use a hint if you get stuck.

A planar linear map has determinant −2. What does it do to areas and orientation?

Hint 1 · Find a starting point

Magnitude gives the area scale, while sign gives orientation.

Hint 2 · Take the next step

Separate |det A| from the sign of det A.

Show the reasoning

Answer: Doubles area and reverses orientation

|−2|=2 doubles area; the negative sign reverses orientation.

Before moving on: what would make one of the other answers wrong? Saying why is part of understanding.

Worked example: use elimination

Row swaps negate a determinant; multiplying one row by kk multiplies it by kk; adding a multiple of one row to another leaves it unchanged. For

A=(120251013),A=\begin{pmatrix}1&2&0\\2&5&1\\0&1&3\end{pmatrix},

subtract twice row one from row two to get row two (0,1,1)(0,1,1). Then subtract row two from row three to get (0,0,2)(0,0,2). No swaps or row scalings were used, so the determinant equals the diagonal product of the resulting upper triangular matrix: 1⋅1⋅2=21\cdot1\cdot2=2.

Geometric reasoning provides a check: dependent columns produce zero volume and zero determinant. A very small determinant, however, depends on the scale and dimension of the matrix; singular values are a more informative way to assess sensitivity.

Practice

  1. Find det⁡(1234)\det\begin{pmatrix}1&2\\3&4\end{pmatrix}.
  2. Find the determinant of a triangular matrix with diagonal 2,−1,52,-1,5.
  3. What happens to a 3×33\times3 determinant when every entry is multiplied by 22?
Show worked solutions
  1. 4−6=−24-6=-2, so area scales by 22 and orientation reverses.
  2. The diagonal product is −10-10.
  3. Each of the three rows is scaled by 22, so the determinant is multiplied by 23=82^3=8.
MAKE IT YOURS

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